please solve this question
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★Heya★
A matrix is said to be a singular matrix if it's determinant = 0
So, let's calculate the determinant of given matrix and put that = 0
=>
4( 8 - 10 ) -x( -2(7-2x) - 18 ) + 6( 20 - 3x ) = 0
=>
32 - 40 + 14x - 4x² - 18x + 120 - 18 x = 0
=>
-4x² - 22x + 112 = 0
=>
2x² + 11x - 56 = 0
=>
x = (-11 ± √{121 + 448})/4
=>
x = ( -11 ±√569 ) / 4
=>
x = ( -11 ± 24 ) /4
=>
x = 13/4 OR x = -35/4
A matrix is said to be a singular matrix if it's determinant = 0
So, let's calculate the determinant of given matrix and put that = 0
=>
4( 8 - 10 ) -x( -2(7-2x) - 18 ) + 6( 20 - 3x ) = 0
=>
32 - 40 + 14x - 4x² - 18x + 120 - 18 x = 0
=>
-4x² - 22x + 112 = 0
=>
2x² + 11x - 56 = 0
=>
x = (-11 ± √{121 + 448})/4
=>
x = ( -11 ±√569 ) / 4
=>
x = ( -11 ± 24 ) /4
=>
x = 13/4 OR x = -35/4
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