Question

please solve this


Question = ABCD is a rectangle and P is a point on AB

I will mark your answer as brainliest ​

Answer 1

1st of all...

What you want to find?

If you want to know the area of triangle,

Use Heron's Formula:

$S=\frac{a+b+c}{2} \\\\S=\frac{20}{2} \\A=\sqrt{s(s-a)(s-b)(s-c)} \\A=\sqrt{20(20-5)(20-6)(20-9)} \\\\A=\sqrt{46200} \\\\A=215 (Approx.)$

Now, if you wanna know the Area Of Rectangle,

We know that,

$Area Of Triangle = \frac{1}{2} * b * h$

Therefore,

$215 = \frac{1}{2} * 9 * h\\h = \frac{430}{9} \\18.67cm$

Now, Area of Rectangle ABCD,

$9*18.67= 168cm^{2}$

Hope it Helps...