please solve this question and give a clear answer
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the answer is the 109joules
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Option(D)
Explanation:
Given : AB + AC = 12 cm and AB ∙ AC = 32cm2
∴ AB = (32/AC)
∴ [(32)/(AC)] + AC = 12
⇒ 32 + AC² - 12AC = 0
⇒ AC² - 12AC + 32 = 0
⇒ AC² - 4AC - 8AC + 32 = 0
⇒ AC(AC - 4) - 8(AC - 4) = 0
⇒ (AC - 4)(AC - 8) = 0
⇒ AC = 4 cm, 8 cm
Let AC = 4 cm Then, AB = 8 cm
Potential energy point A = VA = kq₁q₂[(1/AB) + (1/AC)]
⇒ 9 * 10⁹ * 24 * 10⁻⁶ * 24 * 10⁻⁶[(1/4) + (1/8)] * 10²
⇒ 5184 * 10⁻¹ * (12/32)
⇒ 194.4 J
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