please solve this question as soon as possible
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1
f(x) = ax^3 + bx^2 + cx + d
So,
alpha*beta + beta*gamma + alpha*gamma = c/a
And,
alpha*beta*gamma = -d/a
Therefore,
1/alpha + 1/beta + 1/gamma
= alpha*beta + beta*gamma + alpha*gamma / alpha*beta*gamma
= c/a / -d/a
= c / -d
Therefore
1/alpha + 1/beta + 1/gamma
= c/-d
= - c/d
Hope this helps you !!
So,
alpha*beta + beta*gamma + alpha*gamma = c/a
And,
alpha*beta*gamma = -d/a
Therefore,
1/alpha + 1/beta + 1/gamma
= alpha*beta + beta*gamma + alpha*gamma / alpha*beta*gamma
= c/a / -d/a
= c / -d
Therefore
1/alpha + 1/beta + 1/gamma
= c/-d
= - c/d
Hope this helps you !!
dhruvsh:
welco
Answered by
0
I hope it will help you..
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