Question

Please solve this question based on force

Answer 1

1. weight of meter scale:
since it is in equilibrium,

40×5=20×F
F=200/20=10gf
Weight of scale=10 gf
2. The Fulcrum should be placed at zero cm mark to let it in equilibrium position

Answer 2

1. weight of meter scale:

since it is in equilibrium,

40×25=20×F

F=1000/20=50gf

Weight of scale=50 gf

2. The Fulcrum should be placed at zero cm mark to let it in equilibrium position