Please solve this question below.
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HELLO DEAR,
given that :-
![\sin( \alpha ) + \sin( \beta ) = 2 \sin( \alpha ) + \sin( \beta ) = 2](https://tex.z-dn.net/?f=+%5Csin%28+%5Calpha+%29+%2B+%5Csin%28+%5Cbeta+%29+%3D+2)
we know that:-
the maximum value of sin is 1 and minimum value is 0
0 < sin < 1
according to the questions:-
sin alpha +sin beta =2
it is possible when both the values of sin alpha and sin beta will --1--
1+1=2
hence,
sin alpha =1
=> sin alpha=sin 90°
=> alpha =90°
----;;;-similarly,---------
=> sin beta =1
=> beta =90°
hence, the value of
sin alpha× sin beta
=> sin 90° × sin 90°
=> 1×1 =1
I HOPE ITS HELP YOU DEAR,
THANKS
given that :-
we know that:-
the maximum value of sin is 1 and minimum value is 0
0 < sin < 1
according to the questions:-
sin alpha +sin beta =2
it is possible when both the values of sin alpha and sin beta will --1--
1+1=2
hence,
sin alpha =1
=> sin alpha=sin 90°
=> alpha =90°
----;;;-similarly,---------
=> sin beta =1
=> beta =90°
hence, the value of
sin alpha× sin beta
=> sin 90° × sin 90°
=> 1×1 =1
I HOPE ITS HELP YOU DEAR,
THANKS
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