please solve this question class 9th maths chapter 13
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given :-
inner diameter of the hemispherical bowl = 10cm
therefore inner radius = 10/2 (since we know that diameter is double the Length of it's radius)
= 5cm
to find the cost of tin-plating, we need to first find it's inner curved surface area.
formula to find the inner curved surface area is 2πr²
it's inner curved surface area = 2πr²
= 2 × 22/7 × 5 × 5
= 1100/7cm²
now, given the cost is rupees 16 per 100cm².
➡ cost of 1cm² = 16/100
= rupees 0.16
hence, total cost of tin plating = 1100/7 × 0.16
= 176/7
= rupees 25 (approximately)
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