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Answer:
1.angleDCE=angleABE=60deg
2.a)120deg
b)60deg
Step-by-step explanation:
1.angleEBC=angleECB=60deg(angle of an equilateral triangle)
angleABC=angleDCB=90deg(angle of a square)
therefore angleABE=90-60=30deg
" DCE=90-60=30deg
2.a)since BD=CD
angleCBD=angleBCD=30deg
∠BCD+∠CBD+∠BDC=180(angle sum property)
angleBDC=180-60=120deg
b)angBAC+angBDC=180(property of a cyclic quadrilateral opp. angle sum up to 180deg)
angBAC=180-120=60deg
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