Math, asked by singhradheraman8, 8 months ago

please solve this question fast​

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Answers

Answered by AKM2805
0

Step-by-step explanation:

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Answered by yashahuja312
0

Answer:

1.angleDCE=angleABE=60deg

2.a)120deg

b)60deg

Step-by-step explanation:

1.angleEBC=angleECB=60deg(angle of an equilateral triangle)

angleABC=angleDCB=90deg(angle of a square)

therefore angleABE=90-60=30deg

                   "    DCE=90-60=30deg

2.a)since BD=CD

angleCBD=angleBCD=30deg

 ∠BCD+∠CBD+∠BDC=180(angle sum property)

 angleBDC=180-60=120deg

b)angBAC+angBDC=180(property of a cyclic quadrilateral opp. angle sum up to 180deg)

angBAC=180-120=60deg

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