Question

Please solve this question ... Find the values of x and y .

Answer 1

Hey mate here is your answer.....

x^2 +y^2 -2x +4y +5=0

=>x^2-2x +1+y^2+4y+4=0

=>(x-1)^2+(y+2)^2=0


Now we know that if the sum of two perfect

squares is 0 , then they are individually 0.

so, x-1=0

=>x=1

And, y+2=0

=>y=-2.

so, the value of x is 1 and that of y is -2.


Hope it will help you....

plz mark as the brainliest....