please solve this question friends
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Anyway, we let c = the total number of camels.
We're given that c/4 camels were in the forest, 2√c camels were in the mountains, and 15 camels were at the river. So,
c = c/4 + 2√c + 15
=> isolating √c
√c = 3c/8 - 15/2
=> squaring both sides
c = 9c^2/64 - 45c/8 + 225/4
=> multiplying both sides by 64
64c = 9c^2 - 360c + 3,600
=> moving terms to the LHS
9c^2 - 424c + 3,600 = 0
=> factoring
(9c - 100)(c - 36) = 0
Solutions for c include c = 100/9 and c = 36.
The only integer solution is c = 36. So, there are 36 camels in the herd.
We're given that c/4 camels were in the forest, 2√c camels were in the mountains, and 15 camels were at the river. So,
c = c/4 + 2√c + 15
=> isolating √c
√c = 3c/8 - 15/2
=> squaring both sides
c = 9c^2/64 - 45c/8 + 225/4
=> multiplying both sides by 64
64c = 9c^2 - 360c + 3,600
=> moving terms to the LHS
9c^2 - 424c + 3,600 = 0
=> factoring
(9c - 100)(c - 36) = 0
Solutions for c include c = 100/9 and c = 36.
The only integer solution is c = 36. So, there are 36 camels in the herd.
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