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Q7 and Q8
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7. Let x be any positive integer and b = 3
Euclid's Lemma/ Algorithm
x = 3q + r, where q ≥ 0 and 0 ≤ r < 3. Therefore, every number can be
represented as these three forms. There are three cases.
Case 1:
Let x=3q+0
x²=(3q)²
=3(3q²) Where m is an integer such that m = 3q²
x²=3m
Case 2:
x=(3q+1)
x²=(3q+1)²
x²=9q²+6q+1
=3(3q^2+2q)+1 Where m is an integer such that m = 3q²+2q
x²=3m+1
Case 3:
x=3q+2
x²=(3q+2)²
=9q²+12q+4
=9q²+12q+3+1
=3(3q²+4q+1)+1 Where m is an integer such that m = 3q²+4q+1
x²=3m+1
The square of any positive integer is of the form 3m or 3m+1
____________________________________________________________
8. Let a be any positive integer and b = 3
Euclid's Lemma/ Algorithm
a = 3q + r, where q ≥ 0 and 0 ≤ r < 3 Therefore, every number can be
represented as these three forms. There are three cases.
Case 1: When a = (3q)³
= 9q³
= 3(3q³) Where m is an integer such that m = 3q³
Case 2: When a = 3q + 1,
a³ = (3q +1)³
a³ = 27q³ + 27q² + 9q + 1
a³ = 9(3q³ + 3q² + q) + 1
a³ = 9m + 1 Where m is an integer such that m = (3q³ + 3q² + q)
Case 3: When a = 3q + 2,
a³ = (3q +2)³
a³ = 27q³ + 54q² + 36q + 8
a³ = 9(3q³ + 6q² + 4q) + 8
a³ = 9m + 8 Where m is an integer such that m = (3q³ + 6q² + 4q)
Therefore, the cube of any positive integer is of the form 9m, 9m + 1, or 9m + 8.
____________________________________________________________
☺ ☺ ☺ Hope this Helps ☺ ☺ ☺
Euclid's Lemma/ Algorithm
x = 3q + r, where q ≥ 0 and 0 ≤ r < 3. Therefore, every number can be
represented as these three forms. There are three cases.
Case 1:
Let x=3q+0
x²=(3q)²
=3(3q²) Where m is an integer such that m = 3q²
x²=3m
Case 2:
x=(3q+1)
x²=(3q+1)²
x²=9q²+6q+1
=3(3q^2+2q)+1 Where m is an integer such that m = 3q²+2q
x²=3m+1
Case 3:
x=3q+2
x²=(3q+2)²
=9q²+12q+4
=9q²+12q+3+1
=3(3q²+4q+1)+1 Where m is an integer such that m = 3q²+4q+1
x²=3m+1
The square of any positive integer is of the form 3m or 3m+1
____________________________________________________________
8. Let a be any positive integer and b = 3
Euclid's Lemma/ Algorithm
a = 3q + r, where q ≥ 0 and 0 ≤ r < 3 Therefore, every number can be
represented as these three forms. There are three cases.
Case 1: When a = (3q)³
= 9q³
= 3(3q³) Where m is an integer such that m = 3q³
Case 2: When a = 3q + 1,
a³ = (3q +1)³
a³ = 27q³ + 27q² + 9q + 1
a³ = 9(3q³ + 3q² + q) + 1
a³ = 9m + 1 Where m is an integer such that m = (3q³ + 3q² + q)
Case 3: When a = 3q + 2,
a³ = (3q +2)³
a³ = 27q³ + 54q² + 36q + 8
a³ = 9(3q³ + 6q² + 4q) + 8
a³ = 9m + 8 Where m is an integer such that m = (3q³ + 6q² + 4q)
Therefore, the cube of any positive integer is of the form 9m, 9m + 1, or 9m + 8.
____________________________________________________________
☺ ☺ ☺ Hope this Helps ☺ ☺ ☺
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