Question

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Answer 1

Resistivity of wire A =1.62 *10^-8ohm m
similarly for B =4.68*10^-8 ohm m
let length of the wire be l
Similarly,assume that diameter of wire A is d
Then diameter of of wire B is 2d
We know ,R= rho l/a
so, resistance of wire A :
R A =1.62.10^-8(2l/πd^2/4)
Resistance of wire B:
RB =4.86*10^8(l/π{2d^2/4})
RA /RB = 1.62.8/4.86
=166/81