please solve this question it is very important
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given,
x+y+z=1
xy+yz+xz=-1
xyz=-1
(x+y+z)²=x²+y²+z²+2(xy+yz+zx)
⇒1=x²+y²+z²+2(-1)
⇒x²+y²+z²=1+2
⇒x²+y²+z²=3
we know that,
x³+y³+z³-3xyz=(x+y+z)(x²+y²+z²-xy-yz-zx)
⇒x³+y³+z³-3(-1)=1×(3-(xy+yz+xz)
⇒x³+y³+z³+3=3-(-1)
⇒x³+y³+z³=4-3
⇒x³+y³+z³=1
x+y+z=1
xy+yz+xz=-1
xyz=-1
(x+y+z)²=x²+y²+z²+2(xy+yz+zx)
⇒1=x²+y²+z²+2(-1)
⇒x²+y²+z²=1+2
⇒x²+y²+z²=3
we know that,
x³+y³+z³-3xyz=(x+y+z)(x²+y²+z²-xy-yz-zx)
⇒x³+y³+z³-3(-1)=1×(3-(xy+yz+xz)
⇒x³+y³+z³+3=3-(-1)
⇒x³+y³+z³=4-3
⇒x³+y³+z³=1
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