Question

please solve this question not from NCERT because I am not able to understand it from NCERT so please do it yourself then make me understand

Answer 1

ABCD is a sq and diagonals of sq bisect at 90°

thus AOB is right triangle with OA=OB=x(let)

in ∆AOB by Pythagoras th

AB^2= OA^2+OB^2

56^2= x^2+x^2

x^2. =56×56/2

x= 28√2

ar of shaded region= 2(ar of sector -∆)

=2{(1/4*22/7*28√2*28√2)-1/2×28√2×28√2)}