please solve this question now i have to go for my exams in 10 min
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if this help you
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hi red x i have posted another question please check it out
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(-1/2)^5 × (-1/2)^8 = (-2)^x
=> a^m × a^n = a^(m+n)
=> (-1/2)^5+8 = (-2)^x
=> (-1/2)^13 = (-2)^x
=> (a/b)^m = (b/a)^1/m
=> (-2)^1/13 = (-2)^x
since bases are equal exponents are also equal
=> (-2) got cancelled out
=> 1/13 = x
hope this helps
=> a^m × a^n = a^(m+n)
=> (-1/2)^5+8 = (-2)^x
=> (-1/2)^13 = (-2)^x
=> (a/b)^m = (b/a)^1/m
=> (-2)^1/13 = (-2)^x
since bases are equal exponents are also equal
=> (-2) got cancelled out
=> 1/13 = x
hope this helps
thank you
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thanks to mark me as brainliest
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