Please solve this question please please
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x=3,1
explanation 1/x+2/2x-3=1/x-2
2x-3+2x/2x^2-3x=1/x-2
(4x-3)(x-2)=2x^2-3x
4x^2-3x-8x+6=2x^2-3x
4x^2-11x+6=2x^3-3x
2x^2-8x+6=0
2(x^2-4x+3)=0. taking 2as common
x^2-4x+3=0
x^2-x-3x+3=0
x(x-1)-3(x-1)=0
(x-3)(x-1)=0
x=3,1
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