Question

please solve this question
PROVE IT::--​

Answer 1

Answer:

Step-by-step explanation:

We have to prove LHS = RHS

LHS = ( tan\theta+sec\theta-1 ) / ( tan\theta-sec\theta+1 )

RHS = (sin\theta+1) / cos\theta

Lets Start from LHS

LHS = ( tan\theta+sec\theta-1 ) / (tan\theta-sec\theta+1 )

= ( tan\theta+sec\theta-(sec^{2}\theta-tan^2\theta )) / ( tan\theta-sec\theta+1 )

= (tan\theta+sec\theta-[(sec\theta+tan\theta)(sec\theta-tan\theta)])/(tan\theta-sec\theta+1 )

= (tan\theta+sec\theta[tan\theta-sec\theta+1]) / (tan\theta-sec\theta+1 )

= tan\theta+sec\theta

= [sin\theta/cos\theta] + [1/cos\theta]

= [(sin\theta+1) /cos\theta] = RHS

Hence Proved,

LHS=RHS