Question

Please solve this question quickly

Answer 1

any mistake in ans. u report me.

Answer 2

Question :-

$\sf{ \frac{ {2}^{n + 4} - 2( {2}^{n} )}{2( {2}^{n + 3} )} + {2}^{ - 3} =}$

Answer :-

$\sf{ \frac{ {2}^{n + 4} - 2( {2}^{n} )}{2( {2}^{n + 3} )} + {2}^{ - 3} =} \: 1$

Explanation :-

We have ,

$\rightarrow \sf{ \frac{ {2}^{n + 4} - 2( {2}^{n} )}{2( {2}^{n + 3} )} + {2}^{ - 3} } \: \\ \\ \rightarrow \sf{\: \frac{ {2}^{n + 4} - {2}^{n + 1} }{ {2}^{n + 4} } + {2}^{ - 3} } \\ \\ \rightarrow \sf{ \frac{ {2}^{n + 4} }{ {2}^{n + 4} } - \frac{ {2}^{n + 1} }{ {2}^{n + 4} } + {2}^{ - 3 } } \\ \\ \rightarrow \sf{1 - {2}^{n + 1 - n - 4} + {2}^{ - 3} } \\ \\ \rightarrow \sf{ 1 - {2}^{ - 3} + {2}^{ - 3} } \\ \\ \rightarrow \: 1$

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