Question

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Answer 1

Answer:

A can do a work in = 10 days

B can do a work in = 15 days

$1 \: day \: work \: of \: a \: = \frac{1}{10} \\ 1 \: day \: work \: of \: b \: = \: \frac{1}{15} \\ \\ 1 \: day \: work \: of \: a \: and \: b \: = \frac{1}{10} + \: \frac{1}{15} = \: \\ \frac{3 \: + \: 2}{30} = \frac{5}{30}$

$convert \:it \: into \: lowest \: term \\ \frac{5}{30} = \frac{1}{6}$

$let \: A \: and \: B \: work \: together \: for \: a \: days \: x \: days \: work \: of \\ = A + B = \frac{x}{6} \\ Remaining \: work =1 - \frac{x}{6} \\ It \: is \: given \: that \: A \: can \: do \: the \: remaining \: work \: in \: 5 \: days \: so \\ 1 \: day \: work \: of \: A = \frac{1 - \frac{x}{6} }{6} = \frac{6 - x}{30} \\ \frac{6 - x}{30} = \frac{1}{10} \\ ⇒6 - x = 3 \: \\ ⇒x = 3 \: days$

Therefore A and B worked for 3 days.

Step-by-step explanation:

Hope it helps, Kartik!! :)

Answer 2

Answer:

3 Days

Step By Step Explanation:

Given,

A can do a work in = 10 days

B can do a work in = 15 days

A’s, 1 day's work = 1/10

B’s, 1 day's work = 1/15

(A+B)’s 1 day's work = 1/10 + 1/15 = 3+2/30

Now, let us consider (A+B) worked together for x days.

So, (A+B)’s, x day work = x/6

Remaining Work = 1 - x/6

It is given that,

A can do the remaining work, ( 1 - x/6) in =5 days

So, A’s 1 day's work  = 1 - x/6 whole/5 = 6-x/30

So We Get

1/10 = 6-x/30

》 30/10 = 6-x

》 3 = 6 - x

》 x = 6 - 3 = 3

∴ Both A and B can do the work together in 3 days.

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