Question

please solve this question step by step

Answer 1

$Given : x = 1 - \sqrt{2}$

$= > \frac{1}{x} = \frac{1}{1 - \sqrt{2}} * \frac{1 + \sqrt{2}}{1 + \sqrt{2}}$

$= > \frac{1 + \sqrt{2}}{1^2 - (\sqrt{2})^2}$

$= > \frac{1 + \sqrt{2}}{1 - 2}$

$= > \frac{1 + \sqrt{2}}{-1}$

$= > -1 - \sqrt{2}$

Now,

$= > x - \frac{1}{x} = 1 - \sqrt{2} - (-1 - \sqrt{2})$

= > 2.

Therefore,

= > (x - 1/x)^3 = (2)^3

= 8.

Hope this helps!

Answer 2

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