Question

please solve this question step by step Q-29

Answer 1

using trigonometry

AB = AC sin 45

80 = AC /root 2

AC = 80 root 2

now

BC = AC cos 45

BC = 80 × root 2 × 1/root 2

BC = 80

same way lets apply in right angle triangle DCE

DE = DC Sin 30

80 = DC /2

DC = 80×2 = 160

CE = AC cos 30 = 160 ×( root 3 )/2

CE = 80 root 3

Now in 2 sec distance travel = CE- BC

= 80 root 3 - 80= 80*(root 3-1)

now speed = distance / time

= 80*(root 3 - 1)/ 2

v = 40 * ( root 3 - 1 )

if you want to solve further pit value of root 3 and solve for it.

Answer 2

hi...

I hope this will help you