Question

Please solve this question
$\sec^{4} q \: - \sec {}^{2} q \: = \tan ^{4} q \: + \tan ^{2} q \:$
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Answer 1

Answer:

see the attachment

Step-by-step explanation:

hope its helpful for you

Answer 2

LHS:sec 4 θ−sec 2 θ=sec 2 θ(sec 2 θ−1)=(1+tan 2 θ)tan 2 θ=tan 2 θ+tan 4 θHence LHS = RHS.