Question

Please solve this question
Those who know​

Answer 1

${\large{\bf{\underline{\underline{\purple{Solution}}}}}}$

• the dimensions of the rectangular sheet of paper → 30 cm × 18 cm

${\large{\bf{\underline{\underline{\red{Let \: V¹ And \: V² Be \: the \: vloume}}}}}}$

• As, let take V1 and V2 be the volume of cylinder formed by rolling the sheet which is rectangular in shape along with its length

${\large{\bf{\underline{\underline{\red{: \: 2\pi \: r = 30 →R1 = \frac{30}{2\pi } \: cm}}}}}}$

• So,

• h1 = 18 cm

${\large{\bf{\underline{\underline{\red{→V1 = \pi r²1 \: h1 = ( {\frac{30}{2\pi} }^{2} \times 18cm) }}}}}}$

Now,

• We have to also suppose R2 and he be the radius and height of cylinder .

${\large{\bf{\underline{\underline{\red{→2\pi r \: 2 = \: →r² = \frac{18}{2\pi} \: cm \: }}}}}}$

h2 = 30 cm

${\large{\bf{\underline{\underline{\red{→ V2 = \pi r²2h2 = \pi ( \frac{18}{2\pi} ) \times 30 {cm}^{3} }}}}}}$

Now,

${\large{\bf{\underline{\underline{\red{→ = \frac{v1}{v2} = \frac{ \frac{30}{2\pi}² ×18 } { \frac{18}{2\pi}²× 30 } = \frac{5}{3} }}}}}}$

Hence , → V1 :V2 = 5:3