Question

Please solve this Question Today is my exam...

Answer 1

Hi...☺

Here is your answer...✌

${( - 16)}^{ - 3} \times{ ( \frac{1}{20} ) }^{ - 3} \\ \\ ={ (-16 \times \frac{1}{20} )}^{ - 3} \: \: \: \: \: \: [ \because {a}^{m} \times {b}^{m} = {(ab)}^{m} ] \\ \\ = {(-\frac{4}{5} )}^{ - 3} = {(-\frac{5}{4} )}^{3} \: \: \: \: \: [ \because {a}^{-m}=\frac{1}{{a}^{m}}] \\ \\ = -\frac{125}{64}$

Answer 2

Hey......!!! here is ur answer.....
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Here..... Given that,
(-16)-³×(1/20)-³
=-1/(16)³×20³
=-20³/16³
=-(20/16)³
=-(5/4)³
=-125/64 <<<<<<<<<<<Ans.
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I hope this may help you.......✌️✌️✌️
Thank You.......☺️☺️☺️