please solve this question urgent please
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correct answer is value of threta is 30 degree
2*(√3/2)^2 +1/2 = 3/2+1/2
= 2
I hope this is correct
2*(√3/2)^2 +1/2 = 3/2+1/2
= 2
I hope this is correct
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Answered by
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2cos^2(theta) + sin(theta)=2
sin^2(theta)+ cos^2(theta)=1
cos^2(theta)=1--sin^2(theta)
Substitute in 1st equation...
2{1--sin^2(theta)] + sin(theta)=2
Cancel 2 on both sides
--2sin^2(theta)+sin(theta)=1
sin(theta)=2sin^2(theta)
cancelling sin(theta) on both sides..
2sin(theta)=1 ==》sin(theta)=1/2
theta=30 degree
===================
Hope it helps you...M
sin^2(theta)+ cos^2(theta)=1
cos^2(theta)=1--sin^2(theta)
Substitute in 1st equation...
2{1--sin^2(theta)] + sin(theta)=2
Cancel 2 on both sides
--2sin^2(theta)+sin(theta)=1
sin(theta)=2sin^2(theta)
cancelling sin(theta) on both sides..
2sin(theta)=1 ==》sin(theta)=1/2
theta=30 degree
===================
Hope it helps you...M
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