verify whether -1 and 3 upon 2 are zeroes of the polynomial p(x) =2x power of x is 3 -9x square +x+12
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Answered by
5
p(x)
=2x³-9x²+x+12
= 2(3/2)³-9(3/2)²+(3/2)+12
= 2(27/8)-9(9/4)+3/2+12
= 54/8 - 81/4 + 3/2 + 12
= 54-162+12+96/8
= 162-162/8
= 0/8
= 0
so 3/2 is zero of p(x)
p(x)
= 2x³-9x²+x+12
= 2(-1)³-9(-1)²+(-1)+12
= 2(-1)-9(1)-1+12
= -2-9+11
= -11+11
= 0
so -1 is zero of p (x)
=2x³-9x²+x+12
= 2(3/2)³-9(3/2)²+(3/2)+12
= 2(27/8)-9(9/4)+3/2+12
= 54/8 - 81/4 + 3/2 + 12
= 54-162+12+96/8
= 162-162/8
= 0/8
= 0
so 3/2 is zero of p(x)
p(x)
= 2x³-9x²+x+12
= 2(-1)³-9(-1)²+(-1)+12
= 2(-1)-9(1)-1+12
= -2-9+11
= -11+11
= 0
so -1 is zero of p (x)
Answered by
0
-1
p(-1)=2×(-1)raised to the power 3.. -9(-1) raised to the power 2.. +(-1) +12
= 0. It is the zero of the polynomial.
3/2
p(3/2)=2×(3/2) raised to the power 3.. -9×(3/2) raised to the power 2.. +3/2 +12 =it is not zero of the polynomial
p(-1)=2×(-1)raised to the power 3.. -9(-1) raised to the power 2.. +(-1) +12
= 0. It is the zero of the polynomial.
3/2
p(3/2)=2×(3/2) raised to the power 3.. -9×(3/2) raised to the power 2.. +3/2 +12 =it is not zero of the polynomial
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