Question

Please solve this question very fast please. ​

Answer 1

Answer:

hope you understand this answer better

Answer 2

Answer:

Step-by-step explanation:

1. sinB = AC/BC=8/17

2. tanB=AC/AB=8/15

3. cosC=AC/BC=8/17

4. cotC= AC/AB=8/15

5. (sinBcosC+cosBSinC)=8/17×8/17+15/17×15/17

=64/289+225/289=289/289=1

6. (sec^2C-tan^2C)=(17/8)^2-(15/8)^2

=289/64-225/64=64/64=1

HOPE SO THIS MAY HELP U

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