Question

Please solve this question with 9th grade maths

Answer 1

Answer:

0

Step-by-step explanation:

a + b + c = 6

= a + b + c - 2 - 2 - 2 = 0

= 2 - a + 2 - b + 2 - c = 0

We know that if x + y + z = 0 , x³ + y³ + z³ = 3 xyz .

This means that the given equation in the question will be equal to :

( 2 - a )³ + ( 2 - b )³ + ( 2 - c )³ = 3 ( 2 - a )( 2 - b )( 2 - c ) .

Transpose the right hand side values to the left :

⇒ ( 2 - a )³ + ( 2 - b )³  + ( 2 - c )³ - 3 ( 2 - a )( 2 - b )( 2 - c ) = 0

Hence the value will be 0 .

Answer 2

so, answer is 0
hope it helps :-)