Question

Please Solve this question : √x = x-2

Answer 1

$x = (x - 2) { }^{2} \\ x = x ^{2} - 4x + 4 \\ 0 = x {}^{2} - 4x + 4 - x \\ 0 = x { }^{2} - 5x + 4 \\ x { }^{2} - 5x + 4 = 0$

Answer 2

Here is your answer
$\sqrt{x} = x - 2 \\ ( \sqrt{x} ) {}^{2} = (x - 2) {}^{2} \\ x = x {}^{2} + 4 - 4x \\ x {}^{2} - 4x - x + 4 = 0 \\ x(x - 4) - 1(x - 4) \\ (x - 4)(x - 1) = 0 \\ x = 4 \: \: and \: 1$
Hope it helps you