Question

Please solve this questions from 14 to 23 All questions please​

Answer 1

$14 .\\ \: \: \: \: \: {(3a + 5b)}^{2} - 4 {c}^{2} \\ = (3a + 5b + 2c)(3a + 5b - 2c) \\ 15. \\ \: \: \: \: \: \: {a}^{2} - {b}^{2} - a - b \\ = (a + b)(a - b) - (a + b) \\ = (a + b)(a - b - 1) \\ \: \: \: \: 18 \\ 4 {a}^{2} - 4 {b}^{2} + 4a + 1 \\ ={(2a)}^{2} + 2.2a + 1 - {(2b)}^{2} \\ = {(2a + 1)}^{2} - {(2b)}^{2} \\ = (2a + 2b + 1)(2a - 2b + 1)$

Answer 2

Hey mate,.

18.

4a²-4b²+4a+1

(2a²)+2.2a+1(2b)²

(2a+1)²-(2b)²

(2a+2b+2)(2a-2b+1)

14.

(3a+5b)²-4c²

(3a+5b+2c)(3a+5b-2c)

Hope it will help you