please solve this questionsearch solve that X + Y + root x y = 14 and x squared plus y squared plus x y =
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(X+Y+XY^1/2)=14
SQUARING ON BOTH SIDES
(X+Y+√XY)²=14²
BY USING THE FORMULA
(a + b + c)2 =
a2 + b2 + c2 + 2ab + 2bc + 2ca
x²+y²+xy+2(x)(y)+2(y)(√xy)+2(√xy)(x)=196
x²+y²+xy+2xy+2√xy(x+y)=196
x²+y²+xy=196-2√xy(14)
x²+y²+xy=196-28√xy
______________________________________________________________
(X+Y+XY^1/2)=14
SQUARING ON BOTH SIDES
(X+Y+√XY)²=14²
BY USING THE FORMULA
(a + b + c)2 =
a2 + b2 + c2 + 2ab + 2bc + 2ca
x²+y²+xy+2(x)(y)+2(y)(√xy)+2(√xy)(x)=196
x²+y²+xy+2xy+2√xy(x+y)=196
x²+y²+xy=196-2√xy(14)
x²+y²+xy=196-28√xy
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