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3(cos^2 (90-65) + cos^2 65)/(sin^2(90-63) + sin^2 63) =α/3
3(sin^2 65 + cos^2 65)(cos^2 63 + sin^2 63) =α/3
3=α/3
α=9
3(sin^2 65 + cos^2 65)(cos^2 63 + sin^2 63) =α/3
3=α/3
α=9
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I hope it help u.......
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