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7 sin²ø + 3 cos²ø = 4
Now
7 sin²ø + 3 cos²ø = 4 (sin²ø + cos²ø)
7 sin²ø + 3 cos²ø = 4 sin²ø + 4cos²ø
7 sin²ø - 4sin²ø = 4 cos²ø - 3 cos²ø
3 sin²ø = cos²ø
sin²ø / cos²ø = 1/3
tan²ø = 1/3
tanø = 1/√3
Hence
tanø = 1/√3 = 30°
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ashish9762:
Please, Tell me How you multiply by sin^2 theta + cos^2 theta in LHS.
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