Question

PLEASE SOLVE THIS SET OF QUESTIONS

1) If one of the zeroes of the polynomial ax square + 6x + 2 is -1, find the value of a.

2) Write the degree of quadratic & bi-quadratic equation.

3) Find the quadratic polynomial, the sum & product of whose zeroes are -3 and 2 resp.

4) Find the sum of zeroes of the polynomial 3x square -5x +1.

5) Find the value of p(-2) if p(x) = 3x cube -5.

6) Write the quadratic polynomial, the zeroes of which are root 2 and root -2.

7) What is the remainder if 3x cube + x square + 2x + 5 is divided by 1+ 2x + x square.

8) Represent the zero of the linear polynomial 2x -9 graphically.

9) Find the zeroes of the polynomial 4x square -9 graphically.

10) The graph of polynomial p(x) does not interect the x-axis but intersect y-axis at one point. Find the number of zeroes of p(x).

11) If 2 is one of the zero of polynomial x² + 5x + p. Find the other zero and value of p.​

Answer 1

Answer:

This is answer for question1

This is answer for question1ax^2+6x+2=p(x)

This is answer for question1ax^2+6x+2=p(x)One of the zero is (-1)

This is answer for question1ax^2+6x+2=p(x)One of the zero is (-1)substitute the value of p(x)

This is answer for question1ax^2+6x+2=p(x)One of the zero is (-1)substitute the value of p(x)a(-1)^2+6(-1)+2=0

This is answer for question1ax^2+6x+2=p(x)One of the zero is (-1)substitute the value of p(x)a(-1)^2+6(-1)+2=01a-6+2=0

This is answer for question1ax^2+6x+2=p(x)One of the zero is (-1)substitute the value of p(x)a(-1)^2+6(-1)+2=01a-6+2=01a-4=0

This is answer for question1ax^2+6x+2=p(x)One of the zero is (-1)substitute the value of p(x)a(-1)^2+6(-1)+2=01a-6+2=01a-4=01a=4

This is answer for question1ax^2+6x+2=p(x)One of the zero is (-1)substitute the value of p(x)a(-1)^2+6(-1)+2=01a-6+2=01a-4=01a=4so the value of a is 4

This is answer for question1ax^2+6x+2=p(x)One of the zero is (-1)substitute the value of p(x)a(-1)^2+6(-1)+2=01a-6+2=01a-4=01a=4so the value of a is 4

This is answer for question1ax^2+6x+2=p(x)One of the zero is (-1)substitute the value of p(x)a(-1)^2+6(-1)+2=01a-6+2=01a-4=01a=4so the value of a is 4 Question no.2

This is answer for question1ax^2+6x+2=p(x)One of the zero is (-1)substitute the value of p(x)a(-1)^2+6(-1)+2=01a-6+2=01a-4=01a=4so the value of a is 4 Question no.2Degree of quadratic polynomial -2

This is answer for question1ax^2+6x+2=p(x)One of the zero is (-1)substitute the value of p(x)a(-1)^2+6(-1)+2=01a-6+2=01a-4=01a=4so the value of a is 4 Question no.2Degree of quadratic polynomial -2Degree of biquadratic polynomial-4

This is answer for question1ax^2+6x+2=p(x)One of the zero is (-1)substitute the value of p(x)a(-1)^2+6(-1)+2=01a-6+2=01a-4=01a=4so the value of a is 4 Question no.2Degree of quadratic polynomial -2Degree of biquadratic polynomial-4Question no.3

Alpha+Bitaa =-3

Alpha×Bita=2

The formula to find quadratic polynomialis (x^2-(alpha+bita)x+(alpha ×bita)

now substitute the values into the formula

x^2-(-3)x+2

x^2+3x +2

question no 4

3x^2-5x+1

a=3;b=5;c=1

-b+/-√b^2-4ac÷2a

x=-5+/-√5^2-4(3)(1)÷2(3)

x=-5+/-√25-12÷6

x=-5+/-√13÷6

question no 5

p(-2)=p(x)=3x^3-5

3(-2)^3-5

3(-8)-5

-24-5

-29