Question

please solve this solution fastly​

Answer 1

Answer:

${25}^{x - 1} + 100 = \frac{ {5}^{2x} }{5} \\ {5}^{2x - 2} + 100 = {5}^{2x - 1} \\ \frac{ {5}^{2x} }{25} - \frac{ {5}^{2x} }{5} = - 100 \\ {5}^{2x} ( \frac{ - 4}{25}) = - 100 \\ {5}^{2x} = {5}^{4} \\ 2x = 4 \\ x = 2$