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which standard of this question was?
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Answer:
2ab^2 + 2b^2c + 3ac + b
Step-by-step explanation:
a(b^2 + 3c) - [b^2 (a-2c) - b (2ab + 1)]
= ab^2 +3ac - [(ab^2 - 2b^2c) - (2ab^2 + b)]
= ab^2 + 3ac - ( - ab^2 - 2b^2c - b)
= 2ab^2 + 2b^2c + 3ac + b
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