Question

please solve this sum..​

Answer 1

Answer:

To prove that

cot^2 A (secA-1)/1+sinA + sec^2 A (sin A-1)/(1+secA) = 0

LHS

= cot^2 A (secA-1)(1+secA)(1-sinA)/(1+sinA)(1-sinA)(1+secA)

- sec^2 A (1-sinA)/(1+sec A)

= cot^2 A * tan^2 A (1-sinA)/cos^2 A (1+secA)

- sec^2 A (1-sinA)/(1+secA)

= 1/cos^2 A (1-sinA)/(1+secA)-1/cos^2(1-sinA)/(1+secA)

= 0

= RHS

Hence proved since LHS = RHS

Hope this helps you !

Answer 2

Answer:

Please see the attachment