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Answers
Answer:
1 question - 6m is the initial velocity
Answer :
1) 6 m/s
2) 5 m
Step By Step Explanation :
Hii Mate ✌
1) We know that,
Velocity time relation,
v = u + at ......(1)
where
v = Final velocity
u = Initial Velocity
a = Acceleration
t = Time
In this question, we have,
v = 34 m/s
a = 7 m/s²
t = 4 sec
u = ?
So, putting these values in eq (1), we get
34 = u + 7×4
=> 34 = u + 28
=> u = 34 - 28
=> u = 6 m/s
Hence,
Initial velocity , u = 6m/s
2) When the ball is dropped from a certain height, it will have some stored gravitational energy. This energy can be shown by
Gravitational Potential Energy,
GPE = m x g x h
The potential energy of gravity is directly affected by the height. When the ball is dropped from a 10m height, it loses 50% energy thus affecting the same percentage of height when it bounces back.
Now 50% of the energy lost means 50% of the height also lost on bouncing back. Given height is 10m and when you lose 50% of 10m, left will be 50% of 10m i.e. 5m.
Hence,
The height of the bounce back is hence 50% of 10m i.e. 5m.
100% CORRECT ✔️✔️
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