Question

please solve this sums fast ​

Answer 1

Answer:

(9) ..Hey mate!

Here is yr answer......

Given,

a+b+c = 0

as we know,

a³+b³+c³ - 3abc = (a+b+c)(a²+b²+c² -ab-bc-ac)

a³ + b³ + c³ -3abc = (0)(a²+b²+c²-ab-bc-ac)

a³+b³+c³ -3abc = 0

a³+b³+c³ = 3abc

Hope it helps....

Answer 2

Step-by-step explanation:

Hlw Ji...

Wish U A Veryy Happy Friendship Day....☺❤

♡♡Take Care Ur Self....☺☺

♤♤Enjoy ur day Pgli....❤❤