Please solve this
Answers
Answered by
2
√(x−5)-√(x−8)=√( 2x−17 )
[(√x-5)-(√x-8)]²=2x-17
[(x-5)+(x-8)-{2(√x-5)(√x-8)}]=2x-17
2x-13-2√[(x-5)(x-8)]=2x-17
2√[(x-5)(x-8)]=2x-2x-13+17
2√[(x-5)(x-8)]=4
√[(x-5)(x-8)]=2
(x-5)(x-8)=4
x²-8x-5x+40=2
x²-8x-5x+38=0
x²-13x+38=0
a=1
b=-13
c=38
x=-b+√b²-4ac/2a
x=13+√169-152/2
x=(13+√17)/2 or x=(13-√17)/2
[(√x-5)-(√x-8)]²=2x-17
[(x-5)+(x-8)-{2(√x-5)(√x-8)}]=2x-17
2x-13-2√[(x-5)(x-8)]=2x-17
2√[(x-5)(x-8)]=2x-2x-13+17
2√[(x-5)(x-8)]=4
√[(x-5)(x-8)]=2
(x-5)(x-8)=4
x²-8x-5x+40=2
x²-8x-5x+38=0
x²-13x+38=0
a=1
b=-13
c=38
x=-b+√b²-4ac/2a
x=13+√169-152/2
x=(13+√17)/2 or x=(13-√17)/2
Similar questions