Math, asked by shrinidhipawar39, 3 months ago

Please solve This. thanks you if you did​

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Answered by phantom90
0

Answer:

A fair amount of neutral salts, such as sodium sulfate or sodium chloride, are used to assist the dyeing process. Their function varies depending on the dye class. For example, in direct dyeing, neutral salts increase the aggregation of the dyes inside the fiber pores and render the dye less hydrophilic (Shore, 1995). In acid dyeing, salts function as retarders, giving more level dyeing results.

Step-by-step explanation:

A fair amount of neutral salts, such as sodium sulfate or sodium chloride, are used to assist the dyeing process. Their function varies depending on the dye class. For example, in direct dyeing, neutral salts increase the aggregation of the dyes inside the fiber pores and render the dye less hydrophilic (Shore, 1995). In acid dyeing, salts function as retarders, giving more level dyeing results.

Answered by bhupens12345
0

Answer:

10

Step-by-step explanation:

3+1/x=10/x^2

=4/x= 10/x^2

=4÷x=10÷x^2

=4×10=x×x^2

=40=2x^2

=40=4x

=x=40/4

=x=10

x=10 proved..........

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