please solve this trignometry question.... no spamming
I'll mark brainliest...
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Given:
xsin³∅ + ycos³∅ = sin∅. cos∅
xsin∅= ycos∅
To prove:
x² + y² = 1
Proof:
xsin³∅ + ycos³∅ = sin∅. cos∅
x.sin³∅ + cos²∅.(ycos∅) = sin∅.cos∅
(use xsin∅= ycos∅ in above)
xsin³∅ + cos²∅.xsin∅ = sin∅.cos∅
xsin∅( sin²∅ + cos²∅) = sin∅.cos∅
xsin∅ = sin∅.cos∅
x = cos∅ so, y = sin∅
Also we know, sin²∅ + cos²∅ = 1
Substituting the following values
sin∅ = y cos∅ = x
Hence, x² + y² = 1
HENCE PROVED
:) Hope This Helps!!!
xsin³∅ + ycos³∅ = sin∅. cos∅
xsin∅= ycos∅
To prove:
x² + y² = 1
Proof:
xsin³∅ + ycos³∅ = sin∅. cos∅
x.sin³∅ + cos²∅.(ycos∅) = sin∅.cos∅
(use xsin∅= ycos∅ in above)
xsin³∅ + cos²∅.xsin∅ = sin∅.cos∅
xsin∅( sin²∅ + cos²∅) = sin∅.cos∅
xsin∅ = sin∅.cos∅
x = cos∅ so, y = sin∅
Also we know, sin²∅ + cos²∅ = 1
Substituting the following values
sin∅ = y cos∅ = x
Hence, x² + y² = 1
HENCE PROVED
:) Hope This Helps!!!
RJRishabh:
how was ur hindi paper
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