please solve this urgently
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Hey there!
Thanks for the question!
Given, 3P = 4Q = 6R
3P = 4Q
3/4P = Q
And, 3P = 6R
R = 1/2P
Now, According to angle sum property ,
P + Q + R = 180
P + 3/4P + 1/2P = 180
P ( 1 + 3/4 + 1/2 ) = 180
P ( 4 + 3 + 2 ) / 4 = 180
9P = 180 * 4
P = 20 * 4
P = 80°
Now, Q = 3/4 * 80 = 60°
R = 80/2 = 40°
Therefore, The angles of the triangle are 80 , 60 , 40 respectively
Thanks for the question!
Given, 3P = 4Q = 6R
3P = 4Q
3/4P = Q
And, 3P = 6R
R = 1/2P
Now, According to angle sum property ,
P + Q + R = 180
P + 3/4P + 1/2P = 180
P ( 1 + 3/4 + 1/2 ) = 180
P ( 4 + 3 + 2 ) / 4 = 180
9P = 180 * 4
P = 20 * 4
P = 80°
Now, Q = 3/4 * 80 = 60°
R = 80/2 = 40°
Therefore, The angles of the triangle are 80 , 60 , 40 respectively
kanhaiya12334:
thanks
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