please solve this with steps .its emergency
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Let the diagonals intersect at point O.
triangle AOB is similar to triangle COD by using AA.
angle AOB= COD(vertically opp. angles)
angle OAB=OCD(alternate interior angles)
Therefore ratio of corresponding sides is equal.
AO/OC=AB/CD
1/2=AB/CD (CD>AB)
therefore
CD=2AB
triangle AOB is similar to triangle COD by using AA.
angle AOB= COD(vertically opp. angles)
angle OAB=OCD(alternate interior angles)
Therefore ratio of corresponding sides is equal.
AO/OC=AB/CD
1/2=AB/CD (CD>AB)
therefore
CD=2AB
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PunithAB:
please send with diagram
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