Question

Pls solve the attached question

Answer 1

I hope you got it........

Answer 2

x- a /b + x-b /a =b/ x-a + a/ x-b
or, {a(x-a)+b(x-b)}/ab ={b(x-b)+a(x-a)}/(x-a)(x-b)
or, (ax -a^2 +bx - b^2)/ab=(bx-b^2+ax -a^2)/(x-a)(x-b)
or, 1/ab =1/(x-a)(x-b) .....by cancelling the same numerator on both sides
or, ab =(x-a)(x-b)=x^2-ax-bx+ab
or, ab-ab=x^2-ax-bx
or, 0=x(x-a-b)
or, x{x-(a+b)}=0
so, either x=0 or x =a+b.........as x-(a+b)=0

hence x= a+b ; 0

Thanks.

Hope it helped. ☺️