Question

please solve thissssssssssss

Answer 1

Suppose that the capacitor is connected to a battery, an electric field ${ E }{ 0 }$ is produced. Now, if we insert the dielectric slab of thickness t = d/ 2, the electric field reduces to E.
Now, the gap between plates is divided in two parts, for distance t there is electric field E and for the remaining distance (d—t) the electric field is ${ E }{ 0 }$
If V be the potential difference between the plates of the capacitor, then