Question

please solve very easy 3rd one...​

Answer 1

Answer:

110°

Step-by-step explanation:

Construct PM||AB||DC

Now B=M=35°

Then D=M=75°

M=75°+35°=110°

Answer 2

${\huge{\underline{\underline{\sf{\blue{SOLUTION:-}}}}}}$

$\huge\underline\bold\red{Given}$

⠀⠀⠀⠀⠀• ∠ CDM = 75°

⠀⠀⠀⠀⠀•∠ABM = 35°

$\huge\underline\bold\red{To\: Calculate}$

⠀⠀⠀⠀⠀•Value of x

$\huge\underline\bold\red{ Construction}$

⠀⠀⠀⠀⠀• Draw a line PQ parallel to AB and CD

$\huge\underline\bold\red{ Explanation }$

⠀⠀⠀⠀⠀• ∠ CDM = 75°

⠀⠀⠀⠀⠀•∠ABM = 35°

∠CDM +∠DMQ = 180° { Co- interior angles}

➯ 75° +∠DMQ = 180°

➯ ∠DMQ= 180-75

⠀${\boxed{\red{\tt{∠DMQ= 105° }}}}$

∠ABM +∠BMQ= 180° { Co- interior angles}

➯ ∠35°+ ∠BMQ = 180

➯∠ BMQ = 180° - 35

⠀${\boxed{\red{\tt{∠BMQ= 145°}}}}$⠀⠀

$\tt\huge{\red{X= ∠DMQ+∠BMQ }}$

x ➯ 105° + 145°

⠀⠀⠀⠀⠀${\boxed{\red{\tt{x➯ 250° }}}}$

${\huge{\underline{\underline{\sf{\blue{Hence :-}}}}}}$

⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀$\huge\boxed{\fcolorbox{red} {yellow}{ x➯250°}}$

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