Question

please somebody can solve it​

Answer 1

Answer:

Given,

   2*A= 3*B = 4*C

  TAKE B AND C IN TERMS OF A

  FIRST,

2*A= 3*B

 B= 2A/3------------------------(1)

SECOND EQN,

  2*A = 4*C

   C= 2/4A= 1/2A-------------------------------------(2)

 NOW A:B:C [BY (1) & (2)]

 = A : B:C

 = A: 2A/3 :1/2A

 TAKING L.CM WHICH IS 6

  = 6A : 4A : 3A /6

 MULTIPLYING BY 6 AND DIVIDING BY A

 =  6: 4: 3

HOPE IT HELPS  YOU :)

Step-by-step explanation:

Answer 2

Answer:

A : B : C = 6 : 4 : 3

Step-by-step explanation:

As per the given 1st condition

3B = 2A

∴ $\frac{Ax}{B} = \frac{3}{2}$

∴ Ax : B = 3 : 2

∴ 4C =  2Ay

∴ $\frac{Ay\\}{C} =\frac{4}{2}$

∴ $\frac{Ay}{C} = \frac{2}{1}$

As we know ,

B : Ax = 2 : 3 And,

Ay : C = 2 : 1

As we know,

B = B × Ay

∴ B = 2 × 2

∴ B = 4

C = Ax × C

∴C = 3 × 1

∴C = 3

A = Ax × Ay

∴ A = 3 × 2

∴ A = 6

SOLUTION: