Question

please somebody solve this

Answer 1

Given A= 30°
We know that 2A will be 60°
Hence, sin(2A)= Sin60°= (√3)/2 ⇒ LHS

RHS= {before that, we know tan30°= 1/(√3)

      = {2(tanA)}÷{1+tan²A}
      = {2(tan30°)}÷{1+tan²30°}
      = {2/(√3)}÷{1+(1/3)                                   ∴,tan²30°= {1/(√3)}×{1/(√3)}
      ={2/(√3)}÷{4/3}
      =2/(√3)×3/4
      =1/1×(√3)/2
      =(√3)/2

Hence, LHS=RHS

Answer 2

here's your answer
HOPE IT HELPS YOU