please someone answer this question fast and clear .ill mark the best answer as brainliest
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- 0.0056 D when relaxed since DIA of the eye lens is 2.3cm and we know that radius of a lens is twice its focal length.....and 1/f in metres = power
- and when stretched 4 D............here v= probably infinity and u=25cm......hence f=25 cm then by formula power= 4D..
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1) when object is kept at infinity the ciliary muscles relax.the focal length has the maximum value that is:
u= -infinity
v=2.3 cm
1/f=1/v -1/u
1/f=1/2.3 + 1/infin
1/f=1/2.3+0
f max=2.3 cm
2) when an eye is closer to the object ciliary muscles strain.the focal length decreases.
u= -25 cm
v=2.3 cm
1/f=1/v-1/u
1/f=1/2.3 +1/25
=10/23+1/25
1/f=250+23/575
f=2.1 cm
3) if the position of the object is btw infinity and point of least distance of distinct vision thn the eyelens adjusts its focal length in btw 2.3 and 2.1 which gives a clear vision...
Anonymous:
u find the power okkk
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